A liquid drop of density ' ' is floating half immersed in a liquid of density ' d '. If ' T ' is the surface tension then the diameter of the liquid drop is ( g = acceleration due to gravity)

Step-by-step solution

aligned & Surface Tension = T 2 r & 4 3 r ^3 ~g =2 rT + 1 2 4 3 r ^3 dg aligned array ll & 2 r T= 4 3 r^3 g- ( 4 3 r^3 d g ) 1 2 & 2 T= 4 3 r^2 g ( - d 2 ) & r^2= 2 T 4 3 g ( - d 2 ) & r^2= 3 T g(2 -d) r= 3 T g(2 -d) & Diameter =2 r= 12 T g(2 -d) array