MHT CET20243 May 2024Morning ShiftPhysicsMechanical Properties of FluidsActual
A gardening pipe having an internal radius ' R ' is connected to a water sprinkler having ' n ' holes each of radius ' r '. The water in the pipe has a speed ' v '. The speed of water leaving the sprinkler is
Options
- A( R ^2 r ^2 ) nV
- BR^2 v n r^2
- C( nr ^2 R ^2 ) V
- D( n R^2 r^2 ) V
Correct answer
B. R^2 v n r^2
Step-by-step solution
Using the equation of continuity, we have A ₁ v = A ₂ v ^ where v is speed of water in the pipe and v^ is the speed of water leaving the pipe. Area of the pipe = R ^2 Area of each hole in the sprinkler = r^2 Total area of the holes in the sprinkler =n r^2 R^2 v=n r^2 v^ ...from (i) v ^ = R ^2 v nr ^2