The pressure inside two soap bubbles, (A) is 1.01 and that of (B) is 1.02 atmosphere respectively. The ratio of their respective radii (A to B) is (outside pressure =1 ~atm .)

Step-by-step solution

Outside pressure =1 ~atm Pressure inside first bubble =1.01 ~atm Pressure inside second bubble =1.02 ~atm Excess pressures will be P _ A =1.01-1=0.01 ~atm and P _ B =1.02-1=0.02 ~atm Now, P 1 r r 1 P r _ A r _ B = P _ B P _ A = 0.02 0.01 = 2 1