The pressure inside a soap bubble A is 1.01 atmosphere and that in a soap bubble B is 1.02 atmosphere. The ratio of volume of A to that of B is

Step-by-step solution

Outside pressure =1 ~atm Pressure inside soap bubble A =1.01 ~atm Pressure inside soap bubble B =1.02 ~atm Excess pressures will be aligned & P _ A =1.01-1=0.01 ~atm and & P _ B =1.02-1=0.02 ~atm & Now, P 1 r r 1 P & r _ A r _ B = P _ B P _ A = 0.02 0.01 = 2 1 & Now, V = 4 3 r ^3 & ~V r ^3 & ~V _ A V _ B = ( r _ A r _ B )^3= ( 2 1 )^3= 8 1 aligned