MHT CET202311 May 2023Evening ShiftPhysicsMechanical Properties of FluidsActual
A liquid drop of radius ' R ' is broken into ' n ' identical small droplets. The work done is [ T = surface tension of the liquid]
Options
- A4 R^2 (n^ 2 3 -1 ) T
- B4 R^2 (n^ 1 3 -1 ) T
- C4 R^2 (1-n^ 1 3 ) T
- D4 R^2 (1-n^ 2 3 ) T
Correct answer
B. 4 R^2 (n^ 1 3 -1 ) T
Step-by-step solution
Volume of n smaller droplets = Volume of bigger drop aligned & n 4 3 r ^3= 4 3 R ^3 & R = n ^ 1 3 r & r = R n ^ 1 3 aligned aligned Work done W & = [n 4 r^2-4 R^2 ] T & =4 [n R^2 n^ 2 3 -R^2 ] T & =4 R^2 [n^ 1 3 -1 ] T aligned