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MHT CET20226 Aug 2022Evening ShiftPhysicsMechanical Properties of FluidsActual

Two narrow tube of diameters d₁ and d₂ are joined together to form a Utube open at both ends. If U-tube contains water, the difference in water levels in the limbs is ( T is the surface tension of water, angle of contact is zero and density of water is , g is the acceleration due to gravity)

Options

  1. A4 T g [ d₂-d₁ d₁ d₂ ]
  2. B4 T g [ d₁ d₂ d₁+d₂ ]
  3. C2 T g [ d₂-d₁ d₁ d₂ ]
  4. D2 T g [ d₁+d₂ d₁ d₂ ]

Correct answer

A. 4 T g [ d₂-d₁ d₁ d₂ ]

Step-by-step solution

Consider the situation below: When angle of contact is zero degree, the radius of meniscus equals the radius of tube. Excess pressure in the first tube P₁= 4 T d₁ Excess pressure in the second tube, P₂= 4 T d₂ Hence, the pressure difference in the two limbs of the tube is given by, P=P₁-P₂=h g h= P₁-P₂ g = 4 T g ( 1 d₁ - 1 d₂ )= 4 T g [ d₂-d₁ d₁ d₂ ]

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