A liquid drop having surface energy ' E ' is spread into 216 droplets of the same size. The final surface energy of the droplets is

Step-by-step solution

The correct option is (D). Concept: Surface Energy is proportional to the surface area E 4 R^2 . Considering volume conservation, the size of small droplets r is: V= 4 3 R^3=216 4 3 r^3 Therefore, R =6 r The total surface area of the new 216 droplets is: 216 (4 r^2 ) or 6 (4 R^2 ) Given E 4 R^2 Therefore, the total surface energy of the new droplets would be 6 E