Pressure inside two soap bubbles is 1.01 ~atm and 1.03 ~atm . The ratio between their volumes is (Pressure outside the soap bubble is 1 ~atm )

Step-by-step solution

Excess pressure inside a soap bubble is given by P = P _ i - P ₀= 4 ~T r aligned & P ₁=1.01 ~atm -1 ~atm =0.01 ~atm & P ₂=1.03 ~atm -1 ~atm =0.03 ~atm aligned aligned & P ₁ P ₂ = r ₂ r ₁ & 0.03 0.01 =3= r ₂ r ₁ & V ₂ ~V ₁ = ( r ₂ r ₁ )^3=(3)^3=27 aligned