MHT CET202124 Sep 2021Morning ShiftPhysicsMechanical Properties of FluidsActual
An ice cube of edge 1 ~cm melts in a gravity free container. The approximate surface area of water formed is (water is in the form of spherical drop)
Options
- A(36 )^ 1 / 3 ~cm ^2
- B(24 )^ 1 / 3 ~cm ^2
- C(28 )^ 1 / 3 ~cm ^2
- D(12 )^ 1 / 3 ~cm ^2
Correct answer
A. (36 )^ 1 / 3 ~cm ^2
Step-by-step solution
x =1 ~cm Volume of the cube v = x ^3=1 ~cm ^3 , volume of drop = volume of cube. aligned & 4 3 r^3=x^3=1 ~cm ^3 & r^3= 3 4 or r= ( 3 4 )^ 1 3 & r^2= ( 9 16 ^2 )^ 1 3 aligned Surface area of drop =4 r^2=4 ( 9 16 ^2 )^ 1 3 = (64 ^3 9 16 ^2 )^ 1 3 =(36 )^ 1 3