Water rises to a height of 2 ~cm in a capillary tube. If crosssectional area of the tube is reduced to 1 16 ^ th of initial area, then water will rise to a height of

Step-by-step solution

aligned & h = 2 ~T r g & h ₂ ~h ₁ = r ₁ r ₂ & Area A = r ^2 A r ^2 & A ₁ ~A ₂ = r ₁^2 r ₂^2 or r ₁ r ₂ = A ₁ ~A ₂ = 16 & r ₁ r ₂ =4 & h ₂ ~h ₁ =4 or h ₂=4 ~h ₁=4 2=8 ~cm aligned