Three liquids have same surface tension and densities ₁, Q₂ , and ₃ ( ₁> ₂> ₃ ) . In three identical capillaries, rise of liquid is same. The corresponding angles of contact ₁, ₂ and ₃ are related as

Step-by-step solution

Rise of a liquid in a capillary tube is given by, h = 2 T r g or =h r g / 2 T where = angle of contact, r = radius of capillary tube T = surface tension = density of liquid now given that h , T and r are constants for all three liquids, and ₁> ₂> ₃ , therefore ₁> ₂> ₃ or ₁ < ₂ < ₃ now as the liquid is rising in all three capillaries therefore angles of contact will be acute, 0 ₁ < ₂ < ₃ < 2