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AP EAMCET202317 May 2023Evening ShiftMathematicsCircleActual

The point of intersection of the tangents drawn at the points where the line 2 x-y+3=0 meets the circle x^2+y^2-4 x-6 y+4=0 is

Options

  1. A(-8, 15 2 )
  2. B( -5 2 , 21 4 )
  3. C( 5 2 , -21 4 )
  4. D(8, -15 2 )

Correct answer

B. ( -5 2 , 21 4 )

Step-by-step solution

Given: x^2+y^2-4 x-6 y+4=0 (x-2)^2+(y-3)^2=3^2 The given equation of line is 2 x-y+3=0 The required point is aligned & = (2- 3^2 2 2 2-1 3+3 , 3- 3^2 (-1) 2 2-1.3+3 ) & = (2- 9.2 4 , 3+ 9 4 )= (- 5 2 , 21 4 ) aligned

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