MHT CET202014 Oct 2020Evening ShiftPhysicsMechanical Properties of FluidsActual
Let ^ R ₁ ' and ^ R ₂ ' are radii of two mercury drops. A big mercury drop is formed from them under isothermal conditions. The radius of the resultant drop is
Options
- AR = R ₁²- R ₂²
- BR= R₁+R₂ 2
- CR = R ₁²+ R ₂²
- DR = ( R ₁³+ R ₂³ )^ 1 3
Correct answer
D. R = ( R ₁³+ R ₂³ )^ 1 3
Step-by-step solution
The Volume of the bigger drop is equal to the sum of the volumes of the smaller drops. aligned & 4 3 R³= 4 3 R₁³+ 4 3 R₂³ & R= [3] R₁³+R₂³ aligned