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MHT CET202012 Oct 2020Morning ShiftPhysicsMechanical Properties of FluidsActual

Two small drops of mercury each of radius 'R' coalesce to form a large single drop. The ratio of the total surface energies before and after the change is

Options

  1. A2 : 1
  2. B2^ 1 / 3 : 1
  3. C2: 1
  4. D2^ 2 / 3 : 1

Correct answer

B. 2^ 1 / 3 : 1

Step-by-step solution

4 3 R³ 2= 4 3 R^ 3 R^ =2^ 1 / 3 R Total surface energy before =2 4 R² T (T= surface tension ) Total surface energy after =4 R^ 2 T Ratio = 2 R² R^ 2 = 2 R² 2^ 2 / 3 R² = 2 2^ 2 / 3 =2^ 1- 2 3 =2^ 1 / 3 Ratio =2^ 1 / 3 : 1

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