MHT CET20192 May 2019Morning ShiftPhysicsMechanical Properties of FluidsActual
A metal sphere of radius ‘ R ’ and density ‘ Q 1 ’ is dropped in a liquid of density ‘ σ ’ moves with terminal velocity ‘ V ’. Another metal sphere of same radius and density ‘ Q 2 ’ is dropped in the same liquid, its terminal velocity will be
Options
- AV Q 2 + σ / Q 1 + σ
- BV Q 1 + σ / Q 2 + σ
- CV Q 2 - σ / Q 1 - σ
- DV Q 1 - σ / Q 2 - σ
Correct answer
C. V Q 2 - σ / Q 1 - σ
Step-by-step solution
V T = 2 9 r 2 δ - σ . g n V V T = 2 9 R 2 Q 1 - σ . n g 2 9 R 2 Q 2 - σ . g ⇒ V T = Q 2 - σ . V Q 1 - σ