If the equation of the circle of radius 3 units which touches the circle x^2+y^2+6 x-8 y-11=0 externally at (3,0) is x^2+y^2+2 g x+2 f y+c=0 , then 3 g-4 f+c=

Step-by-step solution

According to question aligned & (3,0)= ( -6 g-9 6+3 , -6 f+12 6+3 ) & 3= -6 g-9 6+3 g=-6 and O= -6 f+12 6+3 f=2 & Given that g^2+f^2-c =3 & 36+4-c=9 c=31 aligned Now, 3 g-4 f+c=-18-8+31=5