A steel ring of radius 'r' is to be fitted over a wooden disc of radius 'R' ( R r ) . The force required to expand the ring so that it fits over the disc is [ Y = Young's modulus of steel, A = area of cross section of wire ]

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A steel ring of radius 'r' is to be fitted over a wooden disc of radius 'R' ( R > r ) . The force required to expand the ring so that it fits over the disc is [ Y = Young's modulus of steel, A = area of cross section of wire ]

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Correct answer: A. YA ( R - r r )

( Y )= F L Ax Young modulus F = AxY L But length =2 r (circumference of ring) Change in length ( x )=2 R -2 r =2 r =2 ( R - r ) Hence force of expansions is F = YA 2 ( R - r ) 2 r = YA ( R - r ) r

A steel ring of radius 'r' is to be fitted over a wooden disc of radius 'R' ( R > r ) . The force required to expand the ring so that it fits over the disc is [ Y = Young's modulus of steel, A = area of cross section of wire ]

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