Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202620 April 2026Morning ShiftPhysicsMotion in One DimensionActual

A boat crosses a river from one bank A to another bank B which is opposite. The distance between them is D. The speed of water is V_W and that of boat relative to water is V_B . If V_B = 2V_W , the time taken by the boat to cross the river directly along AB is ( 30^ = 1 2 ) , ( 30^ = 3 2 )

Options

  1. AD V_B 2
  2. BD 2 V_B
  3. C2D V_B 3
  4. D3 D 2V_B

Correct answer

C. 2D V_B 3

Step-by-step solution

Let the boat be steered at an angle upstream with respect to the line AB to cross the river directly. For the boat to move exactly along AB, the component of its velocity parallel to the river flow must cancel the river's velocity V_W . V_B = V_W Given V_B = 2V_W , substituting this yields: 2V_W = V_W = 1 2 = 30^ The net velocity of the boat along the line AB is the component of V_B perpendicular to the river flow: V = V_B = V_B 30^ = V_B ( 3 2 ) The time taken to cross the river of width D is: t = D V = D V_B 3 2

Practice Motion in One Dimension on Quantrex Academy →

More from Motion in One Dimension

An object is dropped from a certain point A at a height 'h' from the ground. During it's journey straight downwards, the object passes points B and C such that the ratio of time ta 2026A particle moves along a parabolic path y = 9x^2 in such a way that the x component of velocity remains constant. If, the acceleration of the particle is 2j ms⁻² , find the x compo 2026A car, starting from rest, accelerates at a rate of through a distance S, then continues at constant speed for time t and then decelerates at a rate of 2 to come to rest. If the to 2026A car covers the first half of the distance between two places at 40 km/h and another half at 50 km/h. The average speed of the car is 2026The velocity of a particle moving along x -axis is given as V = x^2 - 5x + 4 (in m/s) where x denotes the x -coordinate of the particle in metres. The magnitude of the acceleration 2026If the displacement (s in metre) of a moving particle in terms of time (t in second) is s=t^3-6 t^2+18 t+9 , then the minimum velocity attained by the particle is 2025A ball projected vertically upwards with a velocity 'v' passes through a point P in its upward journey in a time of ' x ' seconds. From there, the time in which the ball again pass 2025The displacement (x) and time (t) graph of a particle moving along a straight line is shown in the figure. The average velocity of the particle in the time of 10 s is 2025 Full Motion in One Dimension list All MHT CET PYQs