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MHT CET202616 April 2026Morning ShiftPhysicsMotion in One DimensionActual

A ball is released from height 'h' which makes perfectly elastic collision with ground. The frequency of periodic vibratory motion is (g=acceleration due to gravity)

Options

  1. A1 2 g 2h
  2. B1 2 2h g
  3. C1 2 g 2h
  4. D1 2 2h g

Correct answer

A. 1 2 g 2h

Step-by-step solution

Time taken by the ball to fall from height h to the ground is given by t = 2h g . Since the collision is perfectly elastic, the ball rebounds with the same speed and reaches the same height h . The time taken to go up is also t = 2h g . The total time period of one complete oscillation is T = 2t = 2 2h g . The frequency of the periodic motion is f = 1 T = 1 2 g 2h . Answer: 1 2 g 2h

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