A stone falls from the top of a tower of height 100 m and at the same time another stone is projected vertically upwards from the ground with a velocity 25 m/s. The two stones meet after

Step-by-step solution

Let the two stones meet after time t . For the stone falling from the top of the tower: Displacement downwards, h₁ = 1 2 gt^2 For the stone projected upwards from the ground: Displacement upwards, h₂ = 25t - 1 2 gt^2 When the two stones meet, the sum of their displacements is equal to the height of the tower. h₁ + h₂ = 100 1 2 gt^2 + 25t - 1 2 gt^2 = 100 25t = 100 t = 4 s