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MHT CET202613 April 2026Evening ShiftPhysicsMotion in One DimensionActual

The velocity time graph of a body moving in a straight line is shown in a figure. The ratio of displacement to distance travelled by the body in time 0 to 10 s is

Options

  1. A1:1
  2. B1:4
  3. C1:2
  4. D1:3

Correct answer

D. 1:3

Step-by-step solution

Displacement is the algebraic sum of the areas under the velocity-time graph, and distance is the sum of their absolute values. Calculating the areas for each time interval: Area for 0 to 2 s: A₁ = 8 2 = 16 m Area for 2 to 4 s: A₂ = -4 2 = -8 m Area for 4 to 8 s: A₃ = 4 4 = 16 m Area for 8 to 10 s: A₄ = -4 2 = -8 m Total displacement = A₁ + A₂ + A₃ + A₄ = 16 - 8 + 16 - 8 = 16 m Total distance = |A₁| + |A₂| + |A₃| + |A₄| = 16 + 8 + 16 + 8 = 48 m Ratio of displacement to distance = 16 48 = 1 3 Thus, the required rati

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