MHT CET202611 April 2026Morning ShiftPhysicsMotion in One DimensionActual
A car passes three points A, B and C at 3 m/s, 6 m/s and 9 m/s respectively in a straight line with uniform acceleration. If distance AB = 60 m then find the distance BC.
Options
- A100 m
- B75 m
- C200 m
- D125 m
Correct answer
A. 100 m
Step-by-step solution
Using the equation of motion v^2 - u^2 = 2as for the interval AB: v_B^2 - v_A^2 = 2a(AB) 6^2 - 3^2 = 2a(60) 36 - 9 = 120a 27 = 120a a = 27 120 = 9 40 m/s ^2 Applying the same equation for the interval BC: v_C^2 - v_B^2 = 2a(BC) 9^2 - 6^2 = 2 9 40 BC 81 - 36 = 9 20 BC 45 = 9 20 BC BC = 45 20 9 = 100 m Answer: 100 m