If a ball is thrown vertically upwards with speed ' u ', the distance covered by it during the last ' t ' second of its ascent is ( g= acceleration due to gravity)

Step-by-step solution

Distance during last t seconds of ascent A ball thrown upward with initial speed u reaches its peak when final velocity is zero. The distance covered in the last t seconds of ascent equals the distance it would fall from rest in time t . For free fall from rest: initial velocity u' = 0 , acceleration g , time t . s = u't + 1 2 gt^2 Substituting u' = 0 : s = 1 2 gt^2 The correct option is D.