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MHT CET202521 Apr 2025Morning ShiftPhysicsMotion in One DimensionActual

The velocity time graph of a body moving in a straight line is shown in figure. The ratio of displacement to distance travelled by the body in time 0 to 8 s is

Options

  1. A8: 5
  2. B3: 5
  3. C5: 9
  4. D7: 4

Correct answer

C. 5: 9

Step-by-step solution

The displacement is the net area under the velocity-time graph, while distance is the total area taken as positive. From t = 0 to 2 s: displacement +6 m, distance 6 m. From t = 2 to 3 s: displacement -2 m, distance 2 m. The remaining segments follow similarly, yielding displacements of +4 , -2 , and +4 m, with distances of 4 , 2 , and 4 m respectively. The total displacement is 6 - 2 + 4 - 2 + 4 = 10 m. The total distance is 6 + 2 + 4 + 2 + 4 = 18 m. The ratio simplifies to 10:18 = 5:9 .

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