A ball is released from the top of a tower of height H m. It takes T second to reach the ground. The height of the ball from the ground after T 4 second is

Step-by-step solution

Let the body be at x from the top after t 4 ~s . x = ut + 1 2 a t ^2= 1 2 a t ^2 ( u=0) x= 1 2 g ( t 4 )^2= g t^2 32 32 x = gt ^2...(i) H = 1 2 gt ^2 2 H = gt ^2...(ii) From (i) and (ii), we get 2 H =32 x x = 2 H 32 Height of the body from the ground = H - 2 H 32 = 15 H 16