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MHT CET202411 May 2024Morning ShiftPhysicsMotion in One DimensionActual

For the velocity-time graph shown in the figure below, the distance covered by the body in last two second of its motion is ' S ₁ '. What is the ratio of ' S₁ ' to the total distance covered by it

Options

  1. A1 2
  2. B1 4
  3. C1 3
  4. D2 3

Correct answer

B. 1 4

Step-by-step solution

Distance covered = Area enclosed by velocity-time graph. Total distance covered in 6 seconds, S= 1 2 2 10+2 10+ 1 2 2 10=40 m Distance covered in last two seconds, aligned & S^ = 1 2 2 10=10 ~m & Fraction of distance = S^ S = 10 40 = 1 4 aligned

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