The position ' x ' of a particle varies with a time as x=a t^2-b t^3 where ' a ' and ' b ' are constants. The acceleration of the particle will be zero at

Step-by-step solution

x=a t^2-b t^3 Differentiating the displacement, we get velocity V =2 at -3 bt t ^2 Differentiating, we get acceleration A=2 a-6 b t Substituting A =0 aligned 0 & =2 a -6 bt & 6 bt =2 a t & = 2 a 6 ~b = a 3 ~b & aligned