A body at rest falls through a height ' h ' with velocity ' V '. If it has to fall down further for its velocity to become three times, the distance travelled in that interval is

Step-by-step solution

The body acquired velocity V when it falls through a height h , starting from rest. aligned & V ^2=2 gh & h = V ^2 2 ~g aligned If it falls further and attains velocity 3 ~V and if the total height through which it falls is h', then aligned & (3 ~V ^2 )=2 gh ^ & 9 ~V ^2=2 gh ^ & h ^ = 9 ~V ^2 2 ~g =9 ~h & h ^ - h =9 ~h - h =8 ~h aligned