MHT CET2016PhysicsMotion in One Dimension
A particle moves along a circle of radius r with constant tangential acceleration. If the velocity of the particle is v at the end of second revolution after the revolution has started then the tangential acceleration is
Options
- Av 2 8 π r
- Bv 2 6 π r
- Cv 2 4 π r
- Dv 2 10 π r
Correct answer
A. v 2 8 π r
Step-by-step solution
Using v 2 - u 2 = 2 a s and u = u 1 and s = 4 π r ∴ 2 a s = v 2 ⇒ v 2 2 s = a = v 2 2 × 4 π r = v 2 8 π r