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MHT CET202620 April 2026Evening ShiftPhysicsMotion in Two DimensionsActual

A car is travelling at 40 m/s on a circular path of radius 40 m. It is increasing its speed at the rate of 2 m/s ^2 . Its net acceleration is (in m/s ^2 ) nearly

Options

  1. A4 m/s ^2
  2. B8 m/s ^2
  3. C16 m/s ^2
  4. D40 m/s ^2

Correct answer

D. 40 m/s ^2

Step-by-step solution

Given v = 40 m/s and R = 40 m . Tangential acceleration, a_t = 2 m/s ^2 . Centripetal acceleration, a_c = v^2 R = 40^2 40 = 40 m/s ^2 . Net acceleration, a = a_c^2 + a_t^2 = 40^2 + 2^2 = 1600 + 4 = 1604 40 m/s ^2 . Answer: 40 m/s ^2

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