The equation of the trajectory of a ball projected at an angle with the horizontal, is given as y = x - gx^2 2 The initial velocity of the ball is [Given : 45^ = 1 , 45^ = 1 2 ]

Step-by-step solution

The standard equation of trajectory of a projectile is given by y = x - gx^2 2u^2 ^2 Comparing this with the given equation y = x - gx^2 2 , we get = 1 = 45^ and g 2u^2 ^2 = g 2 u^2 ^2 = 1 Substituting = 45^ , u^2 ( 1 2 )^2 = 1 u^2 2 = 1 u^2 = 2 u = 2 m/s Answer: 2 , m/s