MHT CET202618 April 2026Evening ShiftPhysicsMotion in Two DimensionsActual
For a projectile motion, the range R is 'n' times the maximum height H. So the angle of projection is
Options
- A⁻¹ ( 2 n )
- B⁻¹ ( 4 n )
- C⁻¹ ( 4 n )
- D⁻¹ ( 2 n )
Correct answer
C. ⁻¹ ( 4 n )
Step-by-step solution
The horizontal range R of a projectile is given by R = u^2 2 g = 2u^2 g The maximum height H is given by H = u^2 ^2 2g Given that R = nH , substituting the expressions for R and H 2u^2 g = n ( u^2 ^2 2g ) Cancelling u^2 g from both sides 2 = n 2 = 4 n = 4 n = ⁻¹ ( 4 n ) Answer: ⁻¹ ( 4 n )