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MHT CET202615 April 2026Evening ShiftPhysicsMotion in Two DimensionsActual

A particle at rest starts moving with constant angular acceleration ' ' in a circular path of radius 'r'. At certain instant, the magnitude of centripetal acceleration is ( 1 3 )^ rd the tangential acceleration. The relation between linear speed (V) and angular acceleration ( ) is

Options

  1. AV = r 3
  2. BV = r 2
  3. CV = r 3
  4. DV = r 3

Correct answer

C. V = r 3

Step-by-step solution

The tangential acceleration of the particle is given by a_t = r . The centripetal acceleration of the particle is given by a_c = V^2 r . According to the given condition, the magnitude of centripetal acceleration is 1 3 of the tangential acceleration: a_c = 1 3 a_t Substituting the expressions for a_c and a_t : V^2 r = 1 3 (r ) V^2 = r^2 3 Taking the square root on both sides: V = r 3 Answer: V = r 3

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