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MHT CET202611 April 2026Morning ShiftPhysicsMotion in Two DimensionsActual

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration a_c is varying with time t as, a_c = k^2 r t^2 . The power delivered to the particle by the forces acting on it is ( K = constant)

Options

  1. Am^2 k^2 r^2 t^2
  2. Bm k^2 r^2 t
  3. C2 m k^2 r^2 t
  4. Dm k^4 r^2 t^5 3

Correct answer

B. m k^2 r^2 t

Step-by-step solution

Given centripetal acceleration a_c = k^2 r t^2 Using the formula a_c = v^2 r : v^2 r = k^2 r t^2 v^2 = k^2 r^2 t^2 v = k r t The kinetic energy of the particle is given by: E = 1 2 m v^2 E = 1 2 m (k r t)^2 = 1 2 m k^2 r^2 t^2 The total power delivered by all forces acting on the particle is equal to the rate of change of its kinetic energy: P = dE dt P = d dt ( 1 2 m k^2 r^2 t^2 ) P = 1 2 m k^2 r^2 (2t) P = m k^2 r^2 t

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