A particle of mass ' m ' moves along a circle of radius ' r ' with constant tangential acceleration. If K.E. of the particle is ' E ' by the end of third revolution after beginning of the motion, then magnitude of tangential acceleration is

Step-by-step solution

aligned & Using 3^ rd equation of motion, & v ^2= u ^2+2 as & v ^2=2 a _ t s .( For u =0) aligned a _ t = v ^2 2 ~s By the end of 3^ rd revolution, distance covered, aligned & s =3(2 r )=6 r & a _ t = v ^2 2 6 r ... (i) aligned aligned & Also, 1 2 mv ^2= E & v ^2= 2 E m ... (ii) aligned Substituting equation (ii) in equation (i), a_t= 2 E 2 6 r m = E 6 r m