Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202210 Aug 2022Evening ShiftPhysicsMotion in Two DimensionsActual

A body moving in a circular path with a constant speed, it has constant

Options

  1. Amomentum
  2. Bkinetic energy
  3. Cacceleration
  4. Dvelocity

Correct answer

B. kinetic energy

Step-by-step solution

We can see that direction of velocity and acceleration change continuously. both are not constant. Momentum is p=m v which depends on velocity and changes with velocity. The only quantities, the speed | v | and the kinetic energy is 1 2 m| v |^2 are constant during uniform circular motion. Therefore, the answer is kinetic energy.

Practice Motion in Two Dimensions on Quantrex Academy →

More from Motion in Two Dimensions

A boy, standing at a certain height, kicks a football horizontally with a velocity of 19.6 ms⁻¹ . What will be the ratio of horizontal and vertical components of velocities after 2 2026From the same point, two stones A and B are thrown simultaneously, A is thrown up vertically with a velocity of 10 ms⁻¹ and B is thrown up with the same velocity at 30^ with the ho 2026Two bodies are projected with the same velocity. If one is projected at an angle of 30^ and the other at 45^ to the horizontal, then the ratio of maximum heights attained is 2026If two bodies A and B are projected with same velocity but with different angles ₁ and ₂ respectively with the horizontal such that both will have same range, then the ratio of tim 2025If the horizontal range of a body projected with a velocity ' u ' is 3 times the maximum height reached by it, then the range of the body is (g - acceleration due to gravity) 2025If the velocity at the maximum height of a projectile projected at an angle of 45^ is 20 ~m ~s ⁻¹ , then the maximum height reached by the projectile is (Acceleration due to gravit 2025If the range of a body projected with a velocity of 60 ~m ~s ⁻¹ is 180 3 ~m , then the angle of projection of the body is (Acceleration due to gravity =10 ~m ~s ⁻² ) 2025If the height of a projectile at a time of 2 s from the beginning of motion is 60 m, then the time of flight of the projectile is (Acceleration due to gravity =10 ~m ~s ⁻² ) 2025 Full Motion in Two Dimensions list All MHT CET PYQs