A bomb is dropped by an aero plane flying horizontally with a velocity 200 ~km / hr and at a height of 980 ~m . At the time of dropping a bomb, the distance of the aero plane from the target on the ground to hit directly is ( g =9.8 ~m / s ^2 . )

Step-by-step solution

The plane is flying horizontally. Hence initial vertical component of the velocity is zero. If it reaches the ground in time t , then aligned & h = 1 2 gt ^2 & t ^2= 2 ~h ~g = 2 980 9.8 =200 & t =10 2 ~s aligned The horizontal component of the velocity is V =200 ~km / hr =200 5 18 = 1000 18 ~m / s The horizontal distance to be covered is d = Vt = 1000 18 10 2 = 10^4 9 2 ~m