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MHT CET20192 May 2019Morning ShiftPhysicsMotion in Two DimensionsActual

The real force ‘ F ’ acting on a particle of mass ‘ m ’ performing circular motion acts along the radius of circle ‘ r ’ and is directed towards the centre of circle. The square root of magnitude of such force is T = p e r i o d i c t i m e

Options

  1. A2 π T m r
  2. BT m r 4 π
  3. C2 π T m r
  4. DT 2 m r 4 π

Correct answer

A. 2 π T m r

Step-by-step solution

F = m ω 2 r F = m 2 π T 2 . r F = 4 π 2 T 2 . m r ⇒ F = 2 π T m r

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