A particle is performing U.C.M. along the circumference of a circle of diameter 50 cm with frequency 2 Hz. The acceleration of the particle in m / s 2 is

Step-by-step solution

Given, diameter of circle, d = 50 cm = 50 × 10 - 2 m And frequency, f = 2 Hz The acceleration of particle in a uniform circular motion can be given as a = ω 2 x Where, ω = angular frequency = 2 π f X = distance from centre = d 2 ⇒ a = 4 π 2 f 2 × d 2 … (i) Substituting given values in Eq. (i), we get a = 4 π 2 × 4 × 50 × 10 - 2 2 = 4 π 2