If a circle of radius 3 passes through the point (7,3) and -has its centre on the line x-y-1=0 , then its equation among the following is

Step-by-step solution

Let c(h, k) be the centre of the given circle. c(h, k) lies on the line x-y-1=0 h-k-1=0 h=k+1 (i) Now, C P is the radius. array lr & C P=3 (C P)^2=9 & (h-7)^2+(k-3)^2=9 & (k-6)^2+(k-3)^2=9 array array ll & 2 k^2-18 k+36=0 & k^2-9 k+18=0 array (k-6)(k-3)=0 k= 6,3 h= 6+1,3+1 = 7,4 Thus, (h, k) (7,6) or (4,3) . When C (7,6) and r=3 Equation of circle (x-7)^2+(y-6)^2=3^2 x^2+y^2-14 x-12 y+76=0 Option (d) is true.