AP EAMCET20226 Jul 2022Evening ShiftMathematicsCircleActual
The radical centre of the circles x^2+y^2+3 x+2 y+1=0x^2+y^2-x+6 y+5=0 and x^2+y^2+5 x-8 y+15=0 is
Options
- A(3,2)
- B(-3,-2) .
- C(2,3)
- D(-2,-3)
Correct answer
A. (3,2)
Step-by-step solution
aligned & Let S₁: x^2+y^2+3 x+2 y+1=0 & S₂: x^2+y^2-x+6 y+5=0 & S₃: x^2+y^2+5 x-8 y+15=0 aligned Let (x, y) be the radical centre, then S₁-S₂=0 and aligned & S₂-S₃=0 & 4 x-4 y-4=0 and -6 x+14 y-10=0 & x=y+1 and 3 x-7 y+5=0 & 3(y+1)-7 y+5=0 3 y+3-7 y+5=0 & -4 y+8=0 & y=2 and x=2+1=3 aligned Radical centre is (3,2) .