AP EAMCET20226 Jul 2022Morning ShiftMathematicsCircleActual
The circle possessing y -axis as its tangent at (0,2) and passing through (-1,0) , also passes through
Options
- A( -3 2 , 0 )
- B( -5 2 , 2 )
- C( -3 2 , 5 2 )
- D(-4,0)
Correct answer
D. (-4,0)
Step-by-step solution
Let (h, k) be centre of circle. Circle touches the y -axis Radius of circle = h Equation of cicle ( x - h )^2+( y - k )^2= h ^2 . It passes through (0,2) h ^2+(2- k )^2= h ^2 k =2 Since, it also passes through (-1,0) (-1,-h)^2+2^2=h^2 h =-5 / 2 Equation of circle: (x+ 5 2 )^2+(y-2)^2= ( 5 2 )^2 Only option (d) (-4,0) satisfied it.