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AP EAMCET202125 Aug 2021Evening ShiftMathematicsCircleActual

The equation of polar of (1,1) with respect to the circle x^2+y^2+4 x+6 y-3=0 is

Options

  1. A2 x + 3y − 1 = 0
  2. B3x + 4y + 8 = 0
  3. C4x + 3y + 2 = 0
  4. D3x + 4y + 2 = 0

Correct answer

D. 3x + 4y + 2 = 0

Step-by-step solution

Given, circle is x^2+y^2+4 x+6 y-3=0 Given, point is P(1,1). Since, equation of polar form of point (x₁, y₁ ) with respect to circle x^2+y^2+2 g x+2 f y+c=0 is x x₁+y y₁+2 g ( x+x₁ 2 )+2 f ( y+y₁ 2 )+c=0 x ×1 + y ×1 + 2(x + 1) + 3(y + 1) − 3 = 0 x + y + 2x + 2 + 3y + 3 − 3 = 0 3 x+4 y+2=0

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