In the logic circuit diagram, when all the four inputs, A, B, C, D are 'one' the outputs Y₁ , Y₂ , Y₃ are respectively (1, 1, 0). When the inputs A and C are changed to zero and B and D are still 'one', then the outputs Y₁ , Y₂ , Y₃ are respectively change to

Step-by-step solution

From the given logic circuit diagram, we can determine the Boolean expressions for the outputs Y₁ , Y₂ , and Y₃ . The output Y₁ is the result of a NOR gate with inputs A and B , followed by a NOT gate: Y₁ = A + B = A + B The output Y₂ is the result of an AND gate with inputs C and D : Y₂ = C D The output Y₃ is the result of a NOR gate with inputs Y₁ and Y₂ : Y₃ = Y₁ + Y₂ Given the new input conditions: A = 0 , B = 1 , C = 0 , and D = 1 . Substituting these values into the expressions: Y₁ = 0 + 1 = 1 Y₂ = 0 1 = 0 Y₃