In common emitter transistor amplifier, the output resistance is 500 k and the current gain = 50 . If power gain of amplifier is 5 10^6 , what is the input resistance?

Step-by-step solution

Given: Output resistance, R_ out = 500 k = 5 10^5 Current gain, = 50 Power gain, A_p = 5 10^6 The power gain of a common emitter amplifier is given by the formula: A_p = ^2 R_ out R_ in Rearranging the formula to solve for input resistance R_ in : R_ in = ^2 R_ out A_p Substituting the given values: R_ in = (50)^2 5 10^5 5 10^6 R_ in = 2500 5 10^5 5 10^6 R_ in = 2500 10 R_ in = 250 Answer: 250