MHT CET202521 Apr 2025Evening ShiftPhysicsSemiconductorsActual
In common emitter mode of a transistor, the current gain is 8 . The input impedance is 25 k and load resistance is 75 k . The power gain is
Options
- A112
- B192
- C224
- D316
Correct answer
B. 192
Step-by-step solution
Power gain in a common emitter transistor relates current gain, voltage gain, input impedance, and load resistance. Given current gain β = 8, input impedance R in = 25 kΩ, and load resistance R L = 75 kΩ, the voltage gain is determined by A V = β × R L / R in . A_V = 8 75 25 = 8 3 = 24 The power gain A P is the product of voltage and current gains: A_P = A_V = 24 8 = 192 . Alternatively, using the direct formula: A_P = ^2 R_L R_ in = 64 3 = 192 . Power gain: 192