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MHT CET202121 Sep 2021Evening ShiftPhysicsSemiconductorsActual

In an ideal junction diode, the current flowing through PQ is (resistance is 2 kilo-ohms)

Options

  1. A2 10⁻³ ~A
  2. B2 10⁻² ~A
  3. C4 10⁻³ ~A
  4. D10⁻³ ~A

Correct answer

C. 4 10⁻³ ~A

Step-by-step solution

The diode is forward biased. The potential difference between P and Q is (3-(-5))=8 ~V . I = V R = 8 2 10^3 =4 10⁻³ ~A

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