A black body is at temperature of 5780 K. The energy of radiation emitted by the body at wavelength 300 nm is U₁ , at wavelength 500 nm is U₂ and that at 900 nm is U₃ respectively. Wien's constant b = 2.89 10^6 nmK . This shows that

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Correct answer: C. U₁ U₃

Using Wien's displacement law, _m T = b . Substituting the given values: _m = 2.89 10^6 5780 = 500 nm The maximum energy of radiation is emitted at _m = 500 nm . Since U₂ corresponds to the energy at 500 nm , it is the maximum energy. Therefore, U₂ > U₁ and U₂ > U₃ . This gives U₁ U₃ . Answer: U₁ U₃

A black body is at temperature of 5780 K. The energy of radiation emitted by the body at wavelength 300 nm is U₁ , at wavelength 500 nm is U₂ and that at 900 nm is U₃ respectively. Wien's constant b = 2.89 10^6 nmK . This shows that

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