An ordinary body cools from 4 to 3 in 't' minutes. The temperature of the body after next 't' minutes is (Assume Newton's law of cooling and room temperature as )

Step-by-step solution

According to Newton's law of cooling, the temperature T at time t is given by: T - T_s = (T_i - T_s)e^ -kt where T_s is the surrounding temperature and T_i is the initial temperature. For the first t minutes, T_i = 4 , T = 3 , and T_s = : 3 - = (4 - )e^ -kt 2 = 3 e^ -kt e^ -kt = 2 3 For the next t minutes, the initial temperature is 3 . Let the final temperature be T' : T' - = (3 - )e^ -kt T' - = 2 ( 2 3 ) = 4 3 T' = + 4 3 = 7 3 Answer: 7 3