What will be the ratio of rate of radiation of metal sphere at two different temperatures T₁ = 527^ C and T₂ = 127^ C

Step-by-step solution

The temperatures in Kelvin are given by: T₁ = 527 + 273 = 800 K T₂ = 127 + 273 = 400 K According to the Stefan-Boltzmann law, the rate of radiation E is proportional to the fourth power of the absolute temperature T : E T^4 Taking the ratio of the rates of radiation at the two temperatures: E₁ E₂ = ( T₁ T₂ )^4 E₁ E₂ = ( 800 400 )^4 E₁ E₂ = 2^4 = 16 The ratio is 16:1 .